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0.014388x^2+1x-2=0
We add all the numbers together, and all the variables
0.014388x^2+x-2=0
a = 0.014388; b = 1; c = -2;
Δ = b2-4ac
Δ = 12-4·0.014388·(-2)
Δ = 1.115104
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1.115104}}{2*0.014388}=\frac{-1-\sqrt{1.115104}}{0.028776} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1.115104}}{2*0.014388}=\frac{-1+\sqrt{1.115104}}{0.028776} $
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